Overview
This lesson links two parts of the wave model: electromagnetic waves are transverse, and transverse
waves can be polarised. You should also know the main regions of the electromagnetic spectrum and use
Malus’s law for plane-polarised light.
What You Need to Know
- All electromagnetic waves are transverse and travel at speed
c in free space.
- The main spectrum order by decreasing wavelength is radio, microwave, infrared, visible,
ultraviolet, X-rays, and gamma rays.
- Visible light has wavelengths of about 400-700 nm in free space.
- Polarisation means the oscillations of a transverse wave are restricted to one plane.
- Longitudinal waves cannot be polarised because their oscillations are along the direction of
travel.
- For plane-polarised electromagnetic waves passing through a polarising filter, use
I = I0 cos^2(theta).
How to Work Through It
- Recall the electromagnetic spectrum order and the visible wavelength range.
- Use transverse-wave diagrams to show the plane of oscillation.
- Compare one polarising filter with two filters at different angles.
- Practise Malus’s law calculations, including angles of 0 degrees, 45 degrees, and 90 degrees.
Check Your Understanding
- Why does polarisation show that light is transverse?
- What happens to transmitted intensity when the filter angle is 90 degrees to the polarisation
direction?
- Which end of the electromagnetic spectrum has the shortest wavelength?
- What wavelength range is visible to the human eye?
Common Mistakes
- Saying that polarisation changes the speed of the wave.
- Applying Malus’s law to unpolarised light when the question only covers plane-polarised light.
- Mixing up wavelength order and frequency order in the electromagnetic spectrum.
- Forgetting that the angle in Malus’s law is between the plane of polarisation and the filter axis.
Next Steps
- Memorise the electromagnetic spectrum order and the visible wavelength range.
- Practise Malus’s law calculations with clear angle labels and units.