Overview
This lesson explains how alternating current can be converted into a one-direction output.
You will compare half-wave and full-wave rectification, link each output graph to its diode circuit,
and explain how a capacitor smooths the rectified output.
What You Need to Know
- Half-wave rectification uses a single diode so only one half-cycle passes through the load.
- Full-wave rectification uses four diodes in a bridge rectifier so both half-cycles produce current
in the same direction through the load.
- Half-wave and full-wave outputs have different graph shapes.
- A smoothing capacitor charges when the rectified p.d. rises and discharges through the load when
the rectified p.d. falls.
- Larger capacitance and larger load resistance usually reduce ripple because discharge is slower.
How to Work Through It
- Start by sketching the original sinusoidal input.
- Sketch the half-wave rectified output and explain which half-cycle is blocked.
- Sketch the full-wave rectified output and trace current through a bridge rectifier.
- Add capacitor smoothing and describe how capacitance and load resistance affect the ripple.
Check Your Understanding
- How is the graph for half-wave rectification different from full-wave rectification?
- Why does a single diode block one half-cycle?
- Why does a bridge rectifier reverse the negative half-cycle through the load?
- How does a smoothing capacitor reduce ripple?
Common Mistakes
- Drawing full-wave rectification as if it removes half the waveform.
- Saying a smoothing capacitor makes the output perfectly constant.
- Forgetting that the capacitor discharges through the load between peaks.
- Confusing diode direction with conventional current direction.
Next Steps
- Practise drawing input, rectified output, and smoothed output graphs.
- Bring a.c. equations and rectification explanations into the practice lesson.